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Terme mit Bruchzahlen

Aufgabe 1

Kürze so weit wie möglich.
a)
\(\dfrac{36}{45}\) =
b)
\(\dfrac{27}{69}\) =
c)
\(\dfrac{56}{35}\) =

Aufgabe 2

Berechne und kürze so weit wie möglich.
a)
\(\begin{array}[t]{rll} \dfrac{11}{13}- \dfrac {9} {13}+ \dfrac {5} {13}&=& & \\[5pt] \end{array}\)
b)
\(\begin{array}[t]{rll} \dfrac{9}{10}+ \dfrac {3} {10}- \dfrac {8} {10}&=& & \\[5pt] \end{array}\)
c)
\(\begin{array}[t]{rll} \dfrac{3}{8} \cdot \dfrac {4} {7}&=& & \\[5pt] \end{array}\)
d)
\(\begin{array}[t]{rll} \dfrac{7}{9} \cdot \dfrac {11} {9}&=& & \\[5pt] \end{array}\)
e)
\(\begin{array}[t]{rll} \dfrac{7}{9} : \dfrac {9} {7}&=& & \\[5pt] \end{array}\)
f)
\(\begin{array}[t]{rll} \dfrac{3}{4} : \dfrac {5} {4}&=& & \\[5pt] \end{array}\)
g)
\(\begin{array}[t]{rll} \dfrac{5}{12}- \dfrac {2} {6}&=& & \\[5pt] \end{array}\)
h)
\(\begin{array}[t]{rll} \dfrac{3}{36}+ \dfrac {9} {4}&=& & \\[5pt] \end{array}\)
i)
\(\begin{array}[t]{rll} \dfrac{9}{12}-\left( \dfrac{2}{6}+ \dfrac{2}{4}\right)&=& \\[5pt] \end{array}\)
j)
\(\begin{array}[t]{rll} \dfrac{3}{4}+ \dfrac{5}{8}+ \dfrac{4}{16}&=& \\[5pt] \end{array}\)
k)
\(\begin{array}[t]{rll} \dfrac{1}{3}+ \dfrac{14}{3}&=& \\[5pt] \end{array}\)
l)
\(\begin{array}[t]{rll} -\dfrac{4}{10}+ \dfrac{3}{5}&=& \\[5pt] \end{array}\)
m)
\(\begin{array}[t]{rll} -\dfrac{3}{7}- \dfrac{4}{14}&=& \\[5pt] \end{array}\)
n)
\(\begin{array}[t]{rll} \dfrac{7}{8}+ \dfrac{6}{10}- \dfrac{5}{10}&=& \\[5pt] \end{array}\)
o)
\(\begin{array}[t]{rll} \dfrac{6}{11}- \dfrac{8}{22}&=& \\[5pt] \end{array}\)
p)
\(\begin{array}[t]{rll} \dfrac{3}{8}+ \dfrac{3}{7}+ \dfrac{3}{7}&=& \\[5pt] \end{array}\)

Aufgabe 3

Berechne ohne kürzen.
a)
\(\begin{array}[t]{rll} \dfrac{1}{2} \cdot \dfrac{3}{4} \cdot \dfrac{4}{5}&=& \\[5pt] \end{array}\)
b)
\(\begin{array}[t]{rll} \dfrac{5}{6} \cdot \dfrac{4}{7} \cdot \dfrac{4}{7}&=& \\[5pt] \end{array}\)
c)
\(\begin{array}[t]{rll} \dfrac{3}{8} : \dfrac{6}{7} : \dfrac{4}{9}&=& \\[5pt] \end{array}\)
d)
\(\begin{array}[t]{rll} \dfrac{4}{9} : \dfrac{11}{5} \cdot \dfrac{7}{3}&=& \\[5pt] \end{array}\)
e)
\(\begin{array}[t]{rll} \dfrac{13}{7} \cdot \dfrac{1}{2} : \dfrac{12}{2}&=& \\[5pt] \end{array}\)
f)
\(\begin{array}[t]{rll} \dfrac{4}{5} \cdot \dfrac{4}{5} : \dfrac{4}{5}&=& \\[5pt] \end{array}\)
g)
\(\begin{array}[t]{rll} -\dfrac{7}{8} \cdot \left(-\dfrac{4}{9}\right) \cdot \left(-\dfrac{6}{7}\right)&=& \\[5pt] \end{array}\)
h)
\(\begin{array}[t]{rll} \dfrac{9}{11} \cdot \left(- \dfrac{6}{8}\right) \cdot \left(-\dfrac{3}{7}\right)&=& \\[5pt] \end{array}\)
i)
\(\begin{array}[t]{rll} \dfrac{6}{7} : \left(-\dfrac{7}{6}\right) \cdot \dfrac{6}{7}&=& \\[5pt] \end{array}\)
j)
\(\begin{array}[t]{rll} \dfrac{9}{7} \cdot \dfrac{4}{5} : \dfrac{7}{2}&=& \\[5pt] \end{array}\)

Aufgabe 4

Achte auf die Klammern und berechne.
a)
\(\begin{array}[t]{rll} \dfrac{8}{9} \cdot \left(\dfrac{4}{5} + \dfrac{4}{5}\right)&=& \\[5pt] \end{array}\)
b)
\(\begin{array}[t]{rll} \left(\dfrac{3}{7} + \dfrac{1}{7}\right) : \dfrac{7}{4}&=& \\[5pt] \end{array}\)
c)
\(\begin{array}[t]{rll} \left(-\dfrac{15}{23} - \dfrac{9}{23}\right) \cdot \left(-\dfrac{2}{3}\right)&=& \\[5pt] \end{array}\)
d)
\(\begin{array}[t]{rll} \dfrac{9}{3} \cdot \dfrac{2}{4} + \dfrac{5}{12}&=& \\[5pt] \end{array}\)
e)
\(\begin{array}[t]{rll} \dfrac{7}{3} : \left(\dfrac{3}{4} + \dfrac{3}{4}\right)&=& \\[5pt] \end{array}\)
f)
\(\begin{array}[t]{rll} \dfrac{2}{11} \cdot \left(\dfrac{7}{8} + \dfrac{6}{4}\right)&=& \\[5pt] \end{array}\)
g)
\(\begin{array}[t]{rll} \left(\dfrac{3}{4} - \dfrac{2}{5}\right) \cdot \left(-\dfrac{4}{6}\right)&=& \\[5pt] \end{array}\)
h)
\(\begin{array}[t]{rll} \dfrac{1}{4}+\dfrac{7}{2} \cdot \dfrac{3}{2} &=& \\[5pt] \end{array}\)
i)
\(\begin{array}[t]{rll} \dfrac{7}{6} + \dfrac{5}{9} : \dfrac{6}{4}&=& \\[5pt] \end{array}\)
j)
\(\begin{array}[t]{rll} \dfrac{4}{5} \cdot \dfrac{2}{3} + \dfrac{5}{3} \cdot \dfrac{7}{5}&=& \\[5pt] \end{array}\)