Terme mit rationalen Zahlen

Aufgabe 1

b)
\(\begin{array}[t]{rll}
\left(-\dfrac{4}{6}\right) - \left(-\dfrac{3}{2}\right) + \dfrac {2}{3} &=& &\\[5pt]

\end{array}\)
d)
\(\begin{array}[t]{rll}
\left(-\dfrac{6}{7}\right) - \dfrac{3}{14}+ \left(-\dfrac{4}{28}\right) &=& &\\[5pt]

\end{array}\)
f)
\(\begin{array}[t]{rll}
\left(-\dfrac{6}{5}\right) - \dfrac {16} {15} + \left(-\dfrac {22}{10}\right) - \left(-\dfrac{15}{25}\right) &=& &\\[5pt]

\end{array}\)

Aufgabe 2

b)
\(\begin{array}[t]{rll}
\left(-\dfrac{8}{9}\right) : \dfrac{2}{5} : \dfrac {3}{4}  &=& &\\[5pt]

\end{array}\)
d)
\(\begin{array}[t]{rll}
\dfrac{10}{3} \cdot \dfrac {4}{6} : \left(-\dfrac {3}{2}\right) &=& &\\[5pt]

\end{array}\)
f)
\(\begin{array}[t]{rll}
\left(-\dfrac{4}{5}\right) \cdot \left(-\dfrac{2}{3}\right) : \left(-\dfrac{6}{9}\right)  &=& &\\[5pt]

\end{array}\)

Aufgabe 3

Denke an "Punkt vor Strichrechnung".
b)
\(\begin{array}[t]{rll}
\dfrac{7}{9}\cdot \dfrac{2}{3}+ \left(-\dfrac {5}{27}\right) &=& &\\[5pt]

\end{array}\)
d)
\(\begin{array}[t]{rll}
\dfrac{6}{9} + \dfrac {5}{12} -\dfrac {3}{4} \cdot \dfrac {6}{3} &=& &\\[5pt]

\end{array}\)
f)
\(\begin{array}[t]{rll}
\left(-\dfrac{8}{9}\right)\cdot \left(-\dfrac{1}{2}\right)+ \dfrac {5}{6}:\left(-\dfrac{3}{4}\right) &=& &\\[5pt]

\end{array}\)